Program Using the long keyword
#include <stdio.h>
int main() {
int a;
long b; // equivalent to long int b;
long long c; // equivalent to long long int c;
double e;
long double f;
printf("Size of int = %zu bytes \n", sizeof(a));
printf("Size of long int = %zu bytes\n", sizeof(b));
printf("Size of long long int = %zu bytes\n", sizeof(c));
printf("Size of double = %zu bytes\n", sizeof(e));
printf("Size of long double = %zu bytes\n", sizeof(f));
return 0;
}
Output
Size of int = 4 bytes Size of long int = 8 bytes Size of long long int = 8 bytes Size of double = 8 bytes Size of long double = 16 bytes
In this program, the sizeof
operator is used to find the size of int
, long
, long long
, double
and long double
variables.
As you can see, the size of long int
and long double
variables are larger than int
and double
variables, respectively.
By the way, the sizeof
operator returns size_t
(unsigned integral type).
The size_t
data type is used to represent the size of an object. The format specifier used for size_t
is %zu
.
Note: The long
keyword cannot be used with float
and char
types.
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